Question #8dc25

1 Answer
Bidesh B.
Nov 14, 2017

#x^2#

Explanation:

use #logAB=logA+logB#
so,
#log6=log3*2=log2+log3=x #
Now
#log18=log(3*3*2)=log3+log2+log3#
So using this we get
#(log3)^2+log2*log3*+log2log3+log2log2#
=#log3(log3+log2)+log2(log3+log2)#
=#(log3+log2)(log3+log2)#
=#x^2#

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