Firstly, we need to determine whether the quantity of
The reaction proceeds as;
This means that for every 1 mol of ethene that reacts we need 3 mols of oxygen.
We are told that we have 32.10g of ethene. This translates to 1.15mols.
This means that to combust 32.10g of ethene, we would need 3.45mols of Oxygen (3 x 1.15 mols). BUT we only have 64.00g of oxygen, so we need to know how many mols of oxygen we have.
2mols is LESS than the 3.45mols of
If we need 1 mol of ethene for 3 mols of oxygen, then 2 mols of oxygen needs 0.67mols of ethene
Now, if you look at the original reaction; 1mol of ethene reacts to produce 2 mols of
We can now work out the mass of
We are however told that the reaction proceeds with a