What volume is occupied by a $3.0mol$ volume of gas that is heated in piston to a temperature of $323.1K$ under a pressure of $0.12*atm$ ?

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Answer 1 · 2017-12-28T09:55:02

I presume you quote pressure with units of $"Pascal"$ ... $101.3*kPa-=1*atm$

And so $"pressure"=(12,156*Pa)/(101.3xx10^3*Pa*atm^-1)=0.12*atm$

And we solve the old Ideal Gas Equation....

$V=(nRT)/P=(3.0*molxx0.0821*(L*atm)/(K*mol)xx323.1*K)/(0.12*atm)$

...I make this volume over $600*L$ .......

What volume is occupied by a 3.0*mol3.0*mol volume of gas that is heated in piston to a temperature of 323.1*K323.1*K under a pressure of 0.12*atm0.12*atm?