Question #d85ec

1 Answer
Nov 20, 2017

#360n+-111.5# for any integer n

Explanation:

Substitute #a=cosx#
#2a^2-2a-1=0#

Using the quadratic formula
#a=(2+-sqrt(4+8))/4#
#a=(1+-sqrt(3))/2#

Substitute #a=cosx# once again
#cosx=(1+-sqrt(3))/2#
We know #cosx# cannot exceed 1, so #(1+sqrt3)/2# is not an answer.
#cosx=(1-sqrt(3))/2#

Solve for x, (using a calculator)
#x=111.5#

Remembering some trig symmetries, #cos(x)=cos(-x)# and that #2pi# can be added and not change the angle, the answer is achieved:
All possible values are #360n+-x# where n is any integer.

So, if you want to stay inside 360 degrees, the answers are 111.5 and 248.5