Question #d4814

1 Answer
Narad T.
Nov 21, 2017

See the proof below

Explanation:

We need

#cotx=cosx/sinx#

#cscx=1/sinx#

#cos^2x+sin^2x=1#

Therefore,

#LHS=1-sin^2x=cos^2x*sin^2x/sin^2x#

#=cos^2x*(1-cos^2x)/sin^2x#

#=cos^2x/sin^2x-1/sin^2x*cos^4x#

#=cot^2x-csc^2x*cos^4x#

#=RHS#

#QED#

Related questions
Impact of this question
196 views around the world
You can reuse this answer
Creative Commons License