Question #45820

1 Answer
Jim S
Nov 22, 2017

#(f*g)(x)=log(x+1)/(x-2)#, #x# #in(-1,2)uu(2,+oo)#

Explanation:

#*# #f(x)=1/(x-2)#

#x-2!=0# #<=># #x!=2#

so #Df=R-{2}# = #(-oo,2)uu(2,+oo)#

#*##g(x)=log(x+1)#

#x+1>0# #<=>x> -1#
so #Dg=(-1,+oo)#

For #x##in##DfnnDg# #=# #(-1,2)uu(2,+oo)#
#(f*g)(x)# #=# #f(x)*g(x)=1/(x-2)*log(x+1)# #=log(x+1)/(x-2)#

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