Question #0e8af

2 Answers
Nov 22, 2017

#(sec^2theta-1)cos^2theta=sec^2thetacos^2theta-cos^2theta=1-cos^2theta,#
#=sin^2theta.#

Nov 22, 2017

#sin^2 theta#

Explanation:

The identity is incomplete as its equivalent part has not been mentioned.
Anyway, the given expression can be simplified as follows:

Using the standard identity #sec^2 theta -1= tan^2 theta#, the given expression becomes #tan^2 theta* cos^2 theta#

#(sin^2 theta)/ (cos^2 theta# * #cos^2 theta#

= #sin^2 theta#