Question #ab6d1

1 Answer
Nov 22, 2017

See below.

Explanation:

We already have a balanced chemical equation, so now the only thing we have to do is the stoichiometry:

Step 1: Convert grams of LiOH into moles using its molar mass.

"10.0 g LiOH"*((1 mol LiOH)/(23.948 grams))="0.418 mols LiOH"

Step 2: Use the mol ratio of LiOH to LiBr to find how many mols of LiBr will be produced.

"0.418 mols LiOH"*((1 mol LiBr)/(1 mol LiOH))="0.418 mols LiBr"

Step 3: Convert mols of LiBr to grams using its molar mass.

"0.418 mols LiBr"*((86.845g)/(1 mol LiBr))="36.3 grams LiBr"

Hope this helps!