Question #39c85

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Answer 1 · 2017-11-24T20:40:28

# F(x) = (3-(3-x^2)^4)^4 , f(x) = 25sqrtx #

You would have to start in the innermost function first:

# f(x) = b[c(b[c(x)])] #

# f(x) = b[c(b[3-x^2])] #

Then input the next sections with the x that you found.

# f(x) = b[c(3-x^2)^4] #

# f(x) = b[3-(3-x^2)^4] #

# f(x) = (3-(3-x^2)^4)^4 #

Part 2:

# f(x) = a(a[d(x)]) #

# f(x) = a(a[sqrt x]) #

# f(x) = a( 5sqrtx) #

# f(x) = 5 (5 sqrt x) = 25sqrtx#