Question #39c85

1 Answer
Nov 24, 2017

F(x) = (3-(3-x^2)^4)^4 , f(x) = 25sqrtx

Explanation:

You would have to start in the innermost function first:

f(x) = b[c(b[c(x)])]

f(x) = b[c(b[3-x^2])]

Then input the next sections with the x that you found.

f(x) = b[c(3-x^2)^4]

f(x) = b[3-(3-x^2)^4]

f(x) = (3-(3-x^2)^4)^4

Part 2:

f(x) = a(a[d(x)])

f(x) = a(a[sqrt x])

f(x) = a( 5sqrtx)

f(x) = 5 (5 sqrt x) = 25sqrtx