Question #4697e

1 Answer
Jan 28, 2018

#4=E#
(Note that my pictures are hugely off scale)enter image source here

Explanation:

This may be one of the problems that requires some thinking before trying.

Let's label what we know. Here, I have created a picture in Paint.

We are trying to solve for #E#.

Hmm. Let's try to label the angles.
We know that the angles #d# and #b# are right angles.
Let's name angle #c# as #x#.
We now have:

Using the fact that the angles of a triangle always add up to 180 degrees, we can figure out angle #a# in terms of #x#.
#90+x+m/_c=180#
=>#x+m/_c=90#
=>#m/_c=90-x#
We now have:
enter image source here

Similarly, we can figure out the missing angles for triangles #adb# and #bdc#

The missing angle for triangle #adb#, #m#, is equal to #180-90-(90-x)#
=>#180-90-(90-x)=m#
=>#90-90+x=m#
=>#x=m#

Similarly, the missing angle for triangle #bdc#, #M# is equal to #180-90-x#
=>#180-90-x=M#
=>#90-x=M#

We label these angles to get the following:
enter image source here

We see that the triangles #adb# and #bdc# are similar using the AAA similarity theorem.(The corresponding angles are congruent)

Basically, we have separated our original triangle to two pieces:
enter image source here
We can now write a proportion. (The ratio of a pair of corresponding sides are equal to other pairs)

We have:
#8/E=E/2#

We can now solve for #E#.
=>#16=E^2#
=>#sqrt16=E#
=>#4=E#