Question #fa294
1 Answer
Nov 29, 2017
Explanation:
#"note that for x = 2"#
#f(2)=16-20-8+12=0#
#rArr(x-2)" is a factor of "f(x)#
#color(red)(2x^2)(x-2)color(magenta)(+4x^2)-5x^2-4x+12#
#=color(red)(2x^2)(x-2)color(red)(-x)(x-2)color(magenta)(-2x)-4x+12#
#=color(red)(2x^2)(x-2)color(red)(-x)(x-2)color(red)(-6)(x-2)cancel(color(magenta)(-12))cancel(+12)#
#rArrf(x)=(x-2)(2x^2-x-6)#
#color(white)(rArrf(x))=(x-2)(x-2)(2x+3)#
#rArr(x-2)^2(2x+3)=0#
#rArrx=2" (multiplicity 2) and "x=-3/2#