Question

Question #11e34

Answer 1

See below.

Explanation:

The values you have are logarithms. You do not say what base logs they are, so I will assume them to be base 10.

I'm not sure exactly what you are confused about, but will try and help.

When you find the logarithm of a number to a given base, what you are doing is representing the number as a power of that base.

For example:

The logarithm of 100 to the base 10 would be 2.

This would be expressed as `log_(10)100=2`

When you raise 10 to the power of 2 you get the number back.

`10^2=100`

In this case the antilogarithm is 100.

When finding antilogarithms on a calculator you use the key marked `10^x` for base 10 logarithms and `e^x` for natural logarithms and put in the value.

From you examples, if they are base 10 logarithms then we just raise 10 to the given numbers.

`10^(1.376)=23.768` ( 3 .d.p.)

`10^(0.6415)=4.380` ( 3 .d.p. )