Question #2eb6f

1 Answer
P dilip_k
Nov 29, 2017

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Let the height of the pole be #x# m and height of the building is #y # m more than the pole.

From figure

#x/45=tan60^@=sqrt3#

#=>x =45sqrt3#m

Again

#y/45=tan30^@=1/sqrt3#

#=>y=45/sqrt3=15sqrt3 m#

So height of the building

#h=x+y =45sqrt3+15sqrt3=60sqrt3~~104#m

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