Question

Question #03d33

Answer 1

The answer is `=sin(x+y)`

Explanation:

Apply the following

`sin(2A)=2sinAcosA`

Here,

`A=(x+y)/2`

Therefore,

`2sin((x+y)/2)cos((x+y)/2)= sin(2*((x+y)/2))`

`=sin(x+y)`