Question

Question #e5863

Answer 1

`Na + 0.5Cl_2 -> NaCl`. Chloride needed to run the reaction: 20.59 grams.

Explanation:

The reaction (`Na + 0.5Cl_2 -> NaCl`) is the answer. Masses of these:

Na: 23 grams; Cl: 35.5 grams. Final product (table salt) has a mass of 58.5 grams/mol.

22 grams of sodium means `22/23 = 0.96` moles of sodium. Therefore, the limiting substance is chloride in here. Final product (sodium chloride): `34/58.5 = 0.58` mol.

It means that you have 0.29 mol of chloride (`Cl_2`) which is `0.29times71 = 20.59` grams.

It means only 0.58 mol of sodium is reacted with chloride. Some sodium will not be used.