Question #e5863

1 Answer
G_Ozdilek
Dec 4, 2017

#Na + 0.5Cl_2 -> NaCl#. Chloride needed to run the reaction: 20.59 grams.

Explanation:

The reaction (#Na + 0.5Cl_2 -> NaCl#) is the answer. Masses of these:

Na: 23 grams; Cl: 35.5 grams. Final product (table salt) has a mass of 58.5 grams/mol.

22 grams of sodium means #22/23 = 0.96# moles of sodium. Therefore, the limiting substance is chloride in here. Final product (sodium chloride): #34/58.5 = 0.58# mol.

It means that you have 0.29 mol of chloride (#Cl_2#) which is #0.29times71 = 20.59# grams.

It means only 0.58 mol of sodium is reacted with chloride. Some sodium will not be used.

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