Question #0be14

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Answer 1 · 2017-11-29T23:57:31

Please see below.

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#(11pi)/6=((12pi)/6)-pi/6=2pi-pi/6=-pi/6#

#sin(-pi/6)=-1/2#

#cos(-pi/6)=sqrt3/2#

#tan(-pi/6)=((sin(-pi/6))/(cos(-pi/6)))=(-1/2)/(sqrt3/2)=-1/2*2/sqrt3=-1/sqrt3=-sqrt3/3#

#cot(-pi/6)=1/tan(-pi/6)=-sqrt3/1=-sqrt3#

#sec(-pi/6)=1/cos(-pi/6)=1/(sqrt3/2)=1*2/sqrt3=2/sqrt3=(2sqrt3)/3#

#csc(-pi/6)=1/sin(-pi/6)=1/(-1/2)=1*-2=-2#