Question #d53c6

1 Answer
Nov 30, 2017

See below.

Explanation:

#sin((-3pi)/4)=color(blue)(-sqrt(2)/2)#

#cos((-3pi)/4)=color(blue)(-sqrt(2)/2)#

Identity: #color(white)(88)tanx=sinx/cosx#

#:.#

#tan((-3pi)/4)=(sin((-3pi)/4))/(cos((-3pi)/4))=(-sqrt(2)/2)/(-sqrt(2)/2)=color(blue)(1)#

Identity:#color(white)(88)cscx=1/sinx#

#csc((-3pi)/4)=1/(sin((-3pi)/4))=1/(-sqrt(2)/2)=(-2sqrt(2))/2=color(blue)(-sqrt(2))#

Identity:#color(white)(88)secx=1/cosx#

#sec((-3pi)/4)=1/cos((-3pi)/4)=1/(-sqrt(2)/2)=(-2sqrt(2))/2=color(blue)(-sqrt(2))#

Identity: #color(white)(88)cotx=1/tanx#

#cot((-3pi)/4)=1/tan((-3pi)/4)=1/((sin((-3pi)/4))/(cos((-3pi)/4)))=1/((-sqrt(2)/2)/(-sqrt(2)/2))=color(blue)(1)#