Question

In a gaseous mixture of THREE components, `P_"Total"=17.3`, `P_"He"=3.16*atm`, `P_"Ar"=1.44*atm`, what is the partial pressure of the third component, `P_"Ne"`? `P_"Ne"={17.3-3.16-1.44}*atm`

Answer 1

The total pressure is the sum of the partial pressures....

Explanation:

So here `P_"Total"=P_"He"+P_"Ne"+P_"Ar"`

`P_"Ne"={17.3-3.16-1.44}*atm`

`P_"Ne"=P_"Total"-P_"He"-P_"Ar"=??*atm`

Answer 2

`12.7 \ "atm"`

Explanation:

Dalton's law of partial pressure states that,

`P_"total"=P_1+P_2+P_3+...+P_n`

where `P_1,P_2,...,P_n` are the pressures of the gases in a system.

Since there are three gases here, we got:

`P_"total"=P_(He)+P_(Ar)+P_(Ne)`

or

`17.3 \ "atm"=3.16 \ "atm"+1.44 \ "atm"+P_(Ne)`

`P_(Ne)=17.3 \ "atm"-3.16 \ "atm"-1.44 \ "atm"`

`=12.7 \ "atm"`