Given an #"empirical formula"# of #CH#, and a #"molecular mass"# of #252gmol^-1#, what is the #"molecular formula"#?

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Answer 1 · 2017-12-06T04:16:14

#"Molecular formula"-=C_18H_36#..........

We know that the #"molecular formula"# is a whole number multiple of the #"empirical formula..."#

And so we solve for #n# in the equation....

#(CH)_n=nxx(12.011+2xx1.00794)*g*mol^-1=252*g*mol^-1#

#n=(252*g*mol^-1)/(14.03*g*mol^-1)=18#

And so #"Molecular formula"-=C_18H_36#..........

Given an #"empirical formula"# of #CH#, and a #"molecular mass"# of #252*g*mol^-1#, what is the #"molecular formula"#?