Question

Question #7c1f2

Answer 1

`x=-3`

`y=1`

Explanation:

We don’t need to manipulate this system of equations, the `y` terms are already opposites, meaning they will cancel out—eliminate—when the equations are added.

So just add the equations:

`\quad2x+cancel(y)=-5`
+`3x-cancel(y)=-10`
._________

`\implies 5x=-15`

`therefore x=-3`

Plug `x` into one equation to solve for `y`:

`2x+y=-5`

`\implies 2(-3)+y=-5`

`\implies -6+y=-5`

`\therefore y=1`

Check the answers by plugging both into an equation:

`3x-y=-10`

`\implies 3(-3)-1=-10`

`\implies -9-1=-10`

`implies -10=-10`

So the answer is correct.