# Question 3b059

Dec 28, 2017

With the reaction,

$P b \left(s\right) + P b {O}_{2} \left(s\right) \to 2 P b O \left(g\right)$

we're asked to determine its enthalpy change. Generally this is accomplished by subtracting the sum of enthalpy of formation of reactants from products.

Hence,

DeltaH^° =(2mol * (-219.0kJ)/(mol)) - (0 + 1mol * (-276.6kJ)/(mol)) approx -161.4kJ#

This reaction is considered exothermic. It releases heat as it progresses.