Question

How would you prepare lead(II) sulfate from lead(II) carbonate ?

Answer 1

I would do it like this:

Explanation:

Lead(II) carbonate is a white solid. You would heat it to constant mass in a crucible. Yellow lead(II) oxide is formed and `sf(CO_2)` is given off:

`sf(PbCO_(3(s))rarrPbO_((s))+CO_(2(g)))`

Lead(II) sulfate is an insoluble salt so must be prepared by precipitation.

Lead(II) oxide is a base and will neutralise nitric acid to form soluble lead(II) nitrate.

About `sf(20cm^(3))` of M nitric acid is warmed in a beaker. Lead(II) oxide is carefully added until traces of unreacted oxide remain on the bottom of the beaker.

This is to ensure that all the acid has been used up. The oxide is INXS.

The mixture is now filtered into a test tube. You should now have a solution of lead(II) nitrate:

`sf(PbO_((s))+2HNO_(3(aq))rarrPb(NO_3)_(2(aq))+2H_2O_((l)))`

A suitable soluble sulfate solution is now taken eg sodium sulfate.

On mixing with the lead(II) nitrate solution a precipitate of insoluble lead(II) sulfate is formed:

`sf(Pb(NO_3)_(2(aq))+Na_2SO_(4(aq))rarrPbSO_(4(s))+2NaNO_(3(aq)))`

The mixture is filtered and the residue of lead(II) sulfate washed and allowed to dry: