Question

Question #e9f07

Answer 1

First, we know that `lim_(x->0) sinx/x=1`
and the greatest integer function returns the largest integer less than or equal to `x` for all real number `x`, for example, `[1]=1`, `[2.5]=2` and `[-2.5]=-3`

`lim_(x->0) [(sin(2x)/x)]`
`=lim_(x->0) [(sin(2x)/(2x)*2)]`
`=[1*2]`
`=[2]`
`=2`

Here is the answer. Hope it can help you.