Question #2ac6b

1 Answer
Dec 10, 2017

It's a way of measuring continuous growth.

Explanation:

The number #e# is very carefully constructed to measure continuous growth. You might've seen this limit for #e#:
#lim_(n->oo)(1+1/n)^n#

Basically what it is is if you multiply by a number infinitely close to #1# at every single instant.

What this means is that you can measure the amount of continuous growth after a certain time period #x# with the expression #e^x#.

You can also do the reverse and measure how much time it would take to get #x# growth using the natural log, log base #e#:
#ln(x)#.

If I wanted to figure out how long it would take me to grow to 10 times as much as I have now (if the growth is continuous, and the interest is a total of #100%# over a year), I'd take #ln(10)# to get roughly #2.3# years.

We can even take it one step further to think about things which have already happened. Say we wanted to figure out when I had half of what I have now (with the same interest and compounding conditions as before). I'd just take #ln(1/2)#, which is approximately equal to #-0.7#. So #0.7# years ago, I had half of what I have now.

You can also raise #e# to a negative exponent to figure out how much you had a certain amount of time ago. Suppose we wanted to figure out how much I had a year ago, we'd take #e^-1# to get around #0.4#. So a year ago, I had roughly #0.4# (or #2/5#) as much as I do now.

I think the reason #e# is useful to us is because a lot of things in nature don't increase at fixed intervals, rather they increase continually, which is why we need #e# to model how these processes work.