Question #3066e

1 Answer
TreeReader
Dec 10, 2017

#f=5.65times10^-14" Hz"#

Explanation:

#v=f*lambda#
velocity = frequency #times# wavelength

So plug in the values you've been given and solve for the frequency:

#lambda=531 color(red)(times 10^-9)"m" - "because it's nanometres"#
#v = 3times10^8 " ms"^-1# (approx. speed of light)

#3times10^8=f*531times10^-9#

#(3times10^8)/(531times10^-9)=f#

#f=5.65times10^-14" Hz"#

Related questions
Impact of this question
927 views around the world
You can reuse this answer
Creative Commons License