Question

Question #8c9ae

Answer 1

`-1`

Explanation:

we will use

`tan(A+B)=(tanA+tanB)/(1-tanAtanB)`

so

`(tan((19pi)/18)-tan((11pi)/36))/(1-tan((19pi)/18)tan((11pi)/36)`

`=tan((38pi-11pi)/36)=tan((27pi)/36)`

`tan((3pi)/4)=-1`