Question #2211e

1 Answer
Dec 12, 2017

To find theta, you need to find the inverse of each function.

Explanation:

Since all of these are in Quadrant 1, they will be positive.

I'll do the first one for you,

#csc theta = 2#

#theta = csc^-1 (2)# #-># change #csc^-1# to #sin^-1# and use reciprocal of #2#

  • simply because there isn't a button on a calculator for #csc^-1#

#theta = sin^-1 (1/2)#

#theta = 30^@#

For radians, use the formula #n * pi/180#

#30 * pi/180 = pi/6#

Now do the same thing for #cos theta = (sqrt2)/2# and #tan theta = 1#. These are easier, as you don't to worry about changing the function.