Question

Question #4410a

Answer 1

`tan28=q/p`

Explanation:

`tan 62 =p/q ; tan28= ?` In right triangle `tan theta= p/q`

where p is perpendicular and q is base. If `theta=62^0` other

two angles are `90^0 and 28^0 ; tan 28^0 = q/p`

If `tan 62 =p/q` then `tan28=q/p` [Ans]

Alternative method: `tan (90-theta)=cot theta`

`:.tan 28 =tan(90-62)=cot 62= 1/tan62= 1/(p/q)=q/p` [Ans]

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