# Question #dfab3

Dec 14, 2017

It is $51$.

#### Explanation:

This is a classic algebra question.

First, define the variables: Let $x$ be the first number, let $x + 1$ be the second number, let $x + 2$ be the third number, and let $x + 3$ be the fourth number

(Since they are consecutive, meaning that they follow one another. For example, $1$, $2$, and $3$ are consecutive).

Secondly, make the equation. Since the $4$ numbers sum to $198$,

$x + x + 1 + x + 2 + x + 3 = 198$

Third, solve the equation:

$4 x + 6 = 198$

$4 x + 6 - 6 = 198 - 6$

$4 x = 192$

$\frac{4 x}{4} = \frac{192}{4}$

$x = 48$

Finally, answer the question: $x + 3$ is the fourth number in the sequence (from above)

$x + 3$

$= 48 + 3$

$= 51$

Therefore, the fourth number in the sequence is $51$.