Question #dfab3

1 Answer

Answer:

It is #51#.

Explanation:

This is a classic algebra question.

First, define the variables: Let #x# be the first number, let #x + 1# be the second number, let #x+2# be the third number, and let #x + 3# be the fourth number

(Since they are consecutive, meaning that they follow one another. For example, #1#, #2#, and #3# are consecutive).

Secondly, make the equation. Since the #4# numbers sum to #198#,

#x + x +1 + x + 2 + x + 3 = 198#

Third, solve the equation:

#4x + 6 = 198#

#4x + 6 - 6 = 198 -6#

#4x = 192#

#(4x)/4 = 192/4#

#x = 48#

Finally, answer the question: #x + 3# is the fourth number in the sequence (from above)

# x + 3 #

#= 48 + 3#

#= 51#

Therefore, the fourth number in the sequence is #51#.