Question #98f52

Question

223 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-12-14T10:10:26

# tantheta=sqrt3.#

Given that, #sin(theta-pi/6)=costheta.#

Expanding the L.H.S., we have,

#sinthetacos(pi/6)-costhetasin(pi/6)=costheta,#

#:. sqrt3/2sintheta-1/2costheta=costheta, i.e., #

# sqrt3sintheta-costheta=2costheta, or,#

# sqrt3sintheta=costheta+2costheta=3costheta,#

# rArr sintheta/costheta=3/sqrt3, i.e.,#

# tantheta=sqrt3.#