Question #f1bde

1 Answer
Narad T.
Dec 14, 2017

See the proof below

Explanation:

We need

#sin^2x+cos^2x=1#

Therefore,

#LHS=(1-cosx)/sinx+sinx/(1-cosx)#

#=((1-cosx)^2+sin^2x)/(sinx(1-cosx))#

#=(1-2cosx+cos^2x+sin^2x)/(sinx(1-cosx))#

#=(2-2cosx)/(sinx(1-cosx))#

#=(2cancel((1-cosx)))/(sinxcancel((1-cosx)))#

#=2cscx#

#=RHS#

#QED#

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