Question

Question #39b7b

Answer 1

No solution.

Explanation:

`7^lnx = e^(lambda lnx)=(e^lnx)^lambda = x^lambda`

but `lambda = ln7` so finally we have

`x^ln7-x^ln7=0 ne 686` and the equations has not solution.

Answer 2

There is no solution. Had the sign between the two terms been `+` instead of `-`, then there would be a solution. Check the problem.

Explanation:

We have `\ln(a^b)=b\ln a`, so:

`\ln(7^{\ln x})=(\ln x)(\ln 7)`

`\ln(x^{\ln 7})=(\ln 7)(\ln x)`

The logarithms are equal, therefore the numbers `7^{\ln x}` and `x^{\ln 7}` are equal, and their difference is never anything other than zero.