Question #a26e1

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Answer 1 · 2018-02-23T12:52:26

FALSE.

Not an identity.

#(secx-1)/(secx+1)=(secx)/(1-cos^2x)#

If #x=pi/3#

#(1/cos(pi/3)-1)/(1/cos(pi/3)+1)=(1/cos(pi/3))/(1-cos^2(pi/3))#

#(1/(1/2)-1)/(1/(1/2)+1)=(1/(1/2))/(1-1/4)#

#1/(3)=(2)/(3/4)#

#1/(3)=8/3color(white)(88)# FALSE

This is not an identity.