Question #e752d
1 Answer
Dec 20, 2017
Explanation:
#"to find the intercepts, that is where "f(x)" crosses"#
#"the x and y axes"#
#• " let x = 0, in the equation for y-intercept"#
#• " let y = 0, in the equation for x-intercepts"#
#x=0toy=-30larrcolor(red)"y-intercept"#
#y=0to2x^2-4x-30=0#
#rArr2(x^2-2x-15)=0#
#rArr2(x-5)(x+3)=0#
#"equate each factor to zero and solve for x"#
#x-5=0rArrx=5#
#x+3=0rArrx=-3#
#rArrx=-3,x=5larrcolor(red)"x-intercepts"#
graph{2x^2-4x-30 [-10, 10, -5, 5]}