Question #0046c

1 Answer
Ratnaker Mehta
Dec 20, 2017

# +-sqrt2#.

Explanation:

Given that, #sinx=1/2secx=1/2*1/cosx :. 2sinxcosx=1#.

If we add #sin^2x+cos^2x# on both sides, we get,

# sin^2x+cos^2x+2sinxcosx=sin^2x+cos^2x+1, i.e., #

#(sinx+cosx)^2=1+1=2#.

#rArr sinx+cosx=+-sqrt2#.

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