What is #1^oo# ?

1 Answer
Dec 23, 2017

#1^oo = 1#

Explanation:

We are reasonably safe with this one, though if you tweak it in any way it can get messy.

What do we mean by #1^oo# ?

Perhaps you think of:

#1^n = overbrace(1 * 1 * ... * 1)^(n " times")#

So:

#1^oo = overbrace(1 * 1 * ... * 1)^(oo " times")#

That's not strictly accurate. #oo# can be thought of as a shorthand for a limiting process. So we could define:

#1^oo = lim_(n->oo) 1^n = lim_(n->oo) 1 = 1#

Footnote

To see some of the dangers in limit calculations, consider:

#lim_(n->oo) (1+1/n)^n#

We might naively put:

#lim_(n->oo) (1+1/n)^n = (1+1/oo)^oo = (1+0)^oo = 1^oo = 1" "# WRONG

Instead we need can find the true value by looking at the actual value for finite values of #n# and then taking the limit as #n->oo#.

Using the binomial theorem we actually find:

#lim_(n->oo) (1+1/n)^n = sum_(k=0)^oo 1/(k!) = e#