Question #c87b5

2 Answers
Dec 27, 2017

In some cases.

More often, when a strong acid results with a strong base, they effectively "neutralize" each other,

#HCl(aq) + NaOH(aq) to NaCl(aq) + H_2O(l)#

A scenario where your statement may be correct is using a hydrated strong base salt (e.g. #Sr(OH)_2*8H_2O#) and dissolving it in a strong acid.

Dec 27, 2017

Answer:

Yes, this is one of the general types of a double displacement reactions.

Explanation:

A double displacement reaction where;

  1. A salt with an acid that forms a salt of the acid and a second acid that is volatile; i.e.,
    #2KNO_3(aq)+H_2SO_4(aq)->K_2SO_4(aq)+color(red)(2HNO_3(g)#(balanced)
    Note:
    #color(red)(HNO_3) " is one of the a highly volatile acids"#
  2. Same reaction of a salt with an acid that may yield a compound that can be decomposed into a #color(red)("gas")# and a #color(blue)("liquid")#; that is,
    #CaCO_3(aq)+2HCl(aq)->CaCl_2(aq)+color(orange)(H_2CO_3)(aq)#(balanced)
    where:
    #color(orange)(H_2CO_3)(aq)->color(red)(CO_2(g))+color(blue)(H_2O(l))#