# Question #e56bc

Dec 26, 2017

#### Answer:

$\lambda \approx 8.6 \times {10}^{-} 9 \text{ m}$

#### Explanation:

Given: $f = 3.50 \times {10}^{16} {\text{ s}}^{-} 1$

Use the equation:

$c = f \lambda$

where c is the the speed of light ($3.0 \times {10}^{8} \text{ m/s}$), $f$ is the frequency (in Hz or ${\text{s}}^{-} 1$), and $\lambda$ is the wavelength (in meters).

Solve the equation for $\lambda$:

$\lambda = \frac{c}{f}$

$\lambda = \left(3.0 \times {10}^{8} {\text{ m/s")/(3.50 xx 10^16" s}}^{-} 1\right)$

$\lambda \approx 8.6 \times {10}^{-} 9 \text{ m}$