# Question #90f8b

Dec 30, 2017

The osmolar concentration of the solution is 0.1192 Osmol/L.

#### Explanation:

An osmole (Osmol) is 1 mol of particles that contribute to the osmotic pressure of a solution.

For example

$\text{CaCl"_2"(s)" → "Ca"^"2+""(aq)" + "2Cl"^"-""(aq)}$
$\textcolor{w h i t e}{l l} \text{1 mol"color(white)(mmmll)"1 mol"color(white)(mmm)"2 mol}$

Thus,

$\text{1 mol CaCl"_2 ≡ "3 Osmol}$

$\text{CaCl"_2}$ osmoles

The molar mass of ${\text{CaCl}}_{2}$ is 110.98 g/mol.

$\text{CaCl"_2color(white)(l) "osmoles" = "3.15" color(red)(cancel(color(black)("g"))) × (1 color(red)(cancel(color(black)("mol"))))/("110.98" color(red)(cancel(color(black)("g")))) × "3 Osmol"/(1 color(red)(cancel(color(black)("mol")))) = "0.085 15 Osmol}$

$\text{KCl}$ osmoles

The molar mass of $\text{KCl}$ is 74.55 g/mol.

$\text{KCl osmoles" = 0.153 color(red)(cancel(color(black)("g"))) × (1 color(red)(cancel(color(black)("mol"))))/(74.55 color(red)(cancel(color(black)("g")))) × "2 Osmol"/(1 color(red)(cancel(color(black)("mol")))) = "0.004 105 Osmol}$

${\text{K"_2"SO}}_{4}$ osmoles

The molar mass of ${\text{K"_2"SO}}_{4}$ is 174.26 g/mol.

$\text{K"_2"SO"_4color(white)(l) "osmolarity" = "1.57" color(red)(cancel(color(black)("g"))) × (1color(red)(cancel(color(black)("mol"))))/("174.26" color(red)(cancel(color(black)("g")))) × "3 Osmol"/(1color(red)(cancel(color(black)("mol")))) = "0.027 03 Osmol}$

Sucrose osmoles

The molar mass is of sucrose is 342.30 g/mol.

$\text{Sucrose osmoles" = 0.994color(red)(cancel(color(black)("g"))) × (1color(red)(cancel(color(black)("mol"))))/(342.30 color(red)(cancel(color(black)("g")))) × "1 Osmol"/(1color(red)(cancel(color(black)("mol")))) = "0.002 904 Osmol/L}$

$\text{Total osmoles" = "(0.085 15 + 0.004 105 + 0.027 03 + 0.002 904) Osmol" = "0.119 19 Osmol}$

$\text{Osmolar concentration" = "osmoles"/"litres" = "0.119 19 Osmol"/"1 L" = "0.1192 Osmol/L}$