Question #47118

Question

221 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-12-31T02:25:38

# 2+4cos t-sin^2 t=-3cos^2 t#

#=> 2+4cos t-1+cos^2 t+3cos^2 t=0#

#=> 4cos^2t +4cost+1=0#

#=> (2cost +1)^2=0#

#=>cost=-1/2=-cos(pi/3)#

#=>cost=cos(pi- pi/3)=cos((2pi)/3)#

#=>t=2npipm(2pi)/3" where "ninZZ#