# Question #1bdae

##### 1 Answer

Dec 31, 2017

#### Explanation:

- Write and balance the equation

#2KClO->2KCl+O_2# - I assumed that the
#mKClO=0.250g# . Per convention, convert it to moles. The molar mass of#KClO=(90.5g)/(mol)# which is obtainable from the periodic table; i.e.,

#etaKClO=0.250cancel(gKClO)xx(1molKClO)/(90.5cancel(gKClO)#

#etaKClO=0.002762mol# - Referring to the balanced equation, find the
#etaO_2# , where:

#=0.002762cancel(molKClO)xx(1molO_2)/(2cancel(molKClO))#

#=0.001381molO_2# - At
#STP# , mol of a gas will occupy a volume of 22.4L. This relationship will serve as the conversion factor to find the volume of#O_2# collected at this condition.

#V_(O_2)=0.001381cancel(molO_2)xx(22.4L" of " O_2)/(1cancel(molO_2))#

#V_(O_2)=0.03094L" of " O_2~~31.0mL" of "O_2#