Question

Question #7673e

Answer 1

See below.

Explanation:

Think that `(x+1)^n = sum_(k=0)^n((n),(k))x^(n-k)`

so considering `x = i^2` and `n = 15` we have

`(i^2+1)^15 = sum_(k=0)^15 ((15),(k))i^(30-2k)`