Question #97cc9

1 Answer
Anthony R.
Jan 2, 2018

#int5/x^2dx=-5/x+"C"#

Explanation:

Given: #int5/x^2dx#

Take out the constant:

#color(blue)5int1/x^2dx#

Solving #int1/x^2dx#

Rewrite the integral as #intx^(-2)dx#

Apply the following procedure: #intx^adx=(x^(a+1))/(a+1)+"C"#

So...

#intx^-2dx=x^(-2+1)/(-2+1)=x^-1/-1=-x^-1=-1/x+"C"#

Bring back the constant:

#color(blue)5*-1/x+"C"=-5/x+"C"#

Related questions
Impact of this question
176 views around the world
You can reuse this answer
Creative Commons License