Question #899b3

1 Answer
Jan 3, 2018

x = (5pi)/12

Explanation:

sinx + cosx = 1/sqrt2

Squaring both sides,
sin^2x + cos^2x + 2sinxcosx = 1/2

As sin^2x + cos^2x = 1
So,
2sinxcosx = -1/2

As sin2x = 2sinxcosx

sin2x = -1/2

sin2x = sin((5pi)/6)

2x = (5pi)/6

x = (5pi)/12

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