The mean of 8, 7, 5, 9, 4, 3, and #k+4# is 6. What is #k#?
2 Answers
Explanation:
The formula for the mean
#barx = (x_1+x_2+x_3+x_4+x_5+x_6+x_7)/7#
Knowing the mean is 6 and the values of the dataset, we can substitute them in:
#6=(8+7+5+9+4+3+(k+4))/7#
This is now an equation with one unknown variable,
#42=8+7+5+9+4+3+(k+4)#
#42=40+k#
#color(white)0 2=k#
We can also test this value of
#barx = (8+7+5+9+4+3+(color(blue)k+4))/7#
#color(white)(barx) = (8+7+5+9+4+3+(color(blue)2+4))/7#
#color(white)(barx) = (36+(6))/7#
#color(white)(barx) = 42/7" "=6#
We do! So we have verified that
Alternate way to find the unknown data point (and
Explanation:
If you know all the data in a set except for one number, and you know the mean, you can find the last number by remembering that the sum of all the differences from the mean is always 0.
To illustrate, our data starts with an 8, and 8 is two more than 6 (the mean). Remember
Next is 7, which is 1 more than the mean. Add
Next: 5. One less than the mean.
Next: 9. Three more than the mean.
Next: 4. Two less.
Next: 3. Three less.
Now we're down to our last data point, and the sum of all the differences so far is 0. Thus, to end with a total difference of 0, the last difference must be the negative of the cumulative differences so far: that is,
#k+4 -6= 0#
Which simplifies quite easily to
#k=2.#