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Answer 1 · 2018-01-10T03:41:55

#1.28g# of isocane.

#C_20H_42# is called isocane.

It has a molar mass of #282.5475g"/"mol#.

This means, in #4.52*10^-3# moles of isocane, there is

#282.5475g*4.52*10^-3=1.28g# of isocane.

Answer 2 · 2018-01-10T03:42:58

#"1.28 g"#

Calculate the molar mass of #"C"_20"H"_42# by taking

#20xx("molar mass C") + 42xx("molar mass H")#

This gives

#20xx"12.011 g/mol" + 42xx"1.0079 g/mol" = "282.5518 g/mol"#

Now, take the molar mass and multiply it by the number of moles.

#("282.5518 g/mol") xx (4.52 * 10^-3 quad "moles")= "1.277134 g"#

Rounded to three sig figs, this is #"1.28 g"#.