# Question 550c5

Jan 10, 2018

The concentration is 0.200 mol/L.

#### Explanation:

Step 1. Calculate the moles of hydrogen chloride

We can use the Ideal Gas Law to do this:

$\textcolor{b l u e}{\overline{\underline{| \textcolor{w h i t e}{\frac{a}{a}} p V = n R T \textcolor{w h i t e}{\frac{a}{a}} |}}} \text{ }$

We can rearrange this equation to get

$n = \frac{p V}{R T}$

In this problem,

$p \textcolor{w h i t e}{l} = \text{100 kPa}$
$V = \text{0.500 L}$
$R = \text{8.314 kPa·L·K"^"-1""mol"^"-1}$
$T = \text{300 K}$

n = (100 color(red)(cancel(color(black)("kPa"))) × 0.500 color(red)(cancel(color(black)("L"))))/(8.314 color(red)(cancel(color(black)("kPa·L·K"^"-1")))"mol"^"-1" × 300 color(red)(cancel(color(black)("K")))) = "0.020 05 mol"#

Step 2. Calculate the concentration of the solution

$c = \text{0.020 05 mol"/"0.100 L" = "0.200 mol/L}$