Question

Question #777f6

Answer 1

`=204.75g`

Explanation:

Given, the required `M` and the needed volume for the solution, the mass of the sodium chloride `(NaCl)` can be computed as;

`"Molarity"(M)=("no. of moles"(eta))/("Li Solution"(V))`

where:

`eta=(mass(m))/("Molar mass"(Mm)`

Now find the molar mass of `NaCl` . Value is obtainable from the periodic table; i.e.,
`NaCl=(58.5g)/(mol)`

Substitute the value of `eta` to the original formula. Rearrange it to isolate the `m` and plug in given values to solve the required data as shown below;

`M=(m/(Mm))/V`

`(m)/(Mm)=MV`

`m=MxxVxxMm`

`m=(3.5cancel(mol))/(cancel(L))xx(1cancel(L))xx(58.5g)/(1cancel(mol))`

`m=204.75g`