Question #e8125

1 Answer
Jan 11, 2018

Normal force= 24 N
Frictional force acting downwards of 9.6 N in magnitude
Acceleration of the system is 1.2 m/s^2

Explanation:

Normal force acting is given by N=F sin 37 i.e the force applied horizontally on the block.
N= 40*(3/5) or 24 N
As the system is being mobilised upward frictional force will be acting against the direction of effective motion.
Its value will be u*N
Or,(0. 40*24)N i.e 9.6 N
Now,let's consider that the system moves upward with acceleration a,so from equation of force we can write,
F cos 37-(u*N+m*g)=m*a
Or,a=1.2 m/s^2