The table #((x:, 3, 4, n, 8),(y:, 5,7,11,15))# describes a linear function. How do you express the function in slope intercept form and find the value of #n# ?
1 Answer
Explanation:
Given:
#((x:, 3, 4, n, 8),(y:, 5,7,11,15))#
We want to find the linear equation and solve for
The equation may be written in the form:
#y = mx+c#
for some constants
This must be satisfied by the table entries we are given.
So:
#{ (color(blue)(5) = color(blue)(3)m+c), (color(blue)(7) = color(blue)(4)m+c), (color(blue)(11) = color(blue)(n)m+c), (color(blue)(15)=color(blue)(8)m+c) :}#
Subtracting the first of these equations from the second, we find:
#2 = m#
Then substituting
#5=3*2+c = 6+c#
Hence:
#c = -1#
Check the fourth equation:
#2*color(blue)(8)-1 = 16-1=color(blue)(15)" "# as required.
Then the third equation becomes:
#2color(blue)(n)-1 = color(blue)(11)#
Add
#2n=12#
Divide both sides by
#n=6#